The shortest distance between the two straight lines \(\frac{x-\frac{4}{3}}{2}=\frac{y+\frac{6}{5}}{3}=\frac{z-\frac{3}{2}}{4}\) and \(\frac{5y+6}{8}=\frac{2z-3}{9}=\frac{3x-4}{5}\) is

\(\sqrt{23}\) \(3\) \(0\) \(6\sqrt{10}\)

\(0\)

Both lines passes through same point