A rope is wound around a hollow cylinder of mass 3 kg and radius 40 cm. What is the angular acceleration of the cylinder if the rope is pulled with a force of 30 N?
Answer & explanation
Correct answer: option 4
\(\tau\) = F × R
and
\(\tau\) = I \(\alpha\)
F x R = I \(\alpha\)
\(\alpha\) = \(\frac{F × R}{I}\)
On substituting values
\(\alpha\) =\(\frac{30×40×10^{-2}}{3×40×40×10^{-4}}\)
\(\alpha\) = 25 rad/s2