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$\underset{x→0}{\lim}(\frac{x}{\tan^{-1}2x})$ is equal to |
0 $\frac{1}{2}$ 1 ∞ |
$\frac{1}{2}$ |
Let $\tan^{-1}2x=θ⇒x=\frac{1}{2}\tan θ$ and x → 0, θ → 0 $⇒\underset{x→0}{\lim}\frac{x}{\tan^{-1}2x}=\underset{θ→0}{\lim}\frac{\frac{1}{2}\tan θ}{θ}=\frac{1}{2}$ |
