In a situation, A is 4 years older than B. After 16 years from this position, A's age will be three times more than his present age and B's age will be five times more than his present age. Find what was the age of A and B two years ago from the starting position.

6 and 2 years

Let the present age of B is = x years 

A is 4 year elder to B .

so age of A = (x + 4) years 

16 years later A will  be thrice times of his present age and B will be 5 times of his present age . 

according to question, 

( 16 + x + 4 ) = 3 ( x+ 4 ) 

     x = 4 

so, the present age of B = 4 years and present age of A = ( 4 + 4 ) = 8 years.

Now age of A and B 2 years ago is 6 years and 2 years respectively.