CUET Preparation Today
CUET
Section B1
Linear Programming
The maximum value of $Z = 4x + y$ for a L.P.P. whose feasible region is given below is:
50
110
120
170
The correct answer is Option (3) → 120 ##
Given L.P.P. is maximise $Z = 4x + y$
Corner points
value of Z $(Z=4x+y)$
$A(0, 50)$
$Z = 4 \times 0 + 50 = 50$
$B(20, 30)$
$Z = 4 \times 20 + 30 = 110$
$C(30, 0)$
$Z = 4 \times 30 + 0 = 120$
$D(0, 0)$
$Z = 0 + 0 = 0$
Maximum value is 120.
