The maximum value of $Z = 4x + y$ for a L.P.P. whose feasible region is given below is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 120 ##
Given L.P.P. is maximise $Z = 4x + y$
|
Corner points |
value of Z $(Z=4x+y)$ |
|
$A(0, 50)$ |
$Z = 4 \times 0 + 50 = 50$ |
|
$B(20, 30)$ |
$Z = 4 \times 20 + 30 = 110$ |
|
$C(30, 0)$ |
$Z = 4 \times 30 + 0 = 120$ |
|
$D(0, 0)$ |
$Z = 0 + 0 = 0$ |
Maximum value is 120.