A 50 Ω resistance and an inductance of \(\frac{2}{3π}H\) are connected in series with power supply of 220 Volt AC of 50 Hz. Choose the correct statement:

Potential difference leads the current by \(tan^{-1}(\frac{4}{3})\)

$R = 50\Omega , X_L = 2\pi fL = 2\pi \times 50\times \frac{2}{3\pi} = \frac{200}{3}\Omega$

$ \text{ Phase difference } tan\phi = \frac{X_L}{R} = \frac{4}{3}$

$\Rightarrow \text{Voltage lead current by }tan^{-1}(\frac{4}{3})$