Area bounded by the curve \(y=x\sin x\) and \(x-\) axis, where \(x=0\) to \(x=2\pi\) is1\(2\pi\)2\(3\pi\)3\(4\pi\)4None of theseAnswer & explanation+Correct answer: option 1\(\begin{aligned}\text{Area}&=\int_{0}^{2\pi}x\sin xdx\\ &=2\pi\end{aligned}\)
