The velocity-time graph of a particle moving in a straight line is shown in figure. The mass of the particle is 2 kg. Work done by all the forces acting on the particle in time interval between t = 0 to t = 10 s is :
Answer & explanation
Correct answer: option 2
From Work-Energy Theorem :
\(W = \Delta KE = K_f - K_i\)
\(W = \frac{1}{2}m(v^2_f - v^2_i)\)
= \(\frac{1}{2} x 2 [-20^2 - 10^2]\)
= 300 J