Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Work Power Energy

Question:

The velocity-time graph of a particle moving in a straight line is shown in figure. The mass of the particle is 2 kg. Work done by all the forces acting on the particle in time interval between t = 0 to t = 10 s is : 

Options:

400 J

300 J

-400 J

-300 J

Correct Answer:

300 J

Explanation:

From Work-Energy Theorem : 

\(W = \Delta KE = K_f - K_i\)

\(W = \frac{1}{2}m(v^2_f - v^2_i)\)

  = \(\frac{1}{2} x 2 [-20^2 - 10^2]\)

  = 300 J