Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Three-dimensional Geometry

Question:

If the two lines $\frac{x-1}{2}=\frac{y-3}{4}=-z$ and $\frac{x-4}{3}=\frac{y-1}{-2}=z-1$ are contained in a plane then the equation of the plane is:

Options:

$2 x-5 y-16 z+13=0$

$2 x+5 y-16 z+7=0$

$2 x-5 y+11 z+13=0$

$2 x-5 y-16 z-13=0$

Correct Answer:

$2 x-5 y-16 z+13=0$

Explanation:

The correct answer is Option (1) → $2 x-5 y-16 z+13=0$