CUET Preparation Today
If the two lines $\frac{x-1}{2}=\frac{y-3}{4}=-z$ and $\frac{x-4}{3}=\frac{y-1}{-2}=z-1$ are contained in a plane then the equation of the plane is: |
$2 x-5 y-16 z+13=0$ $2 x+5 y-16 z+7=0$ $2 x-5 y+11 z+13=0$ $2 x-5 y-16 z-13=0$ |
$2 x-5 y-16 z+13=0$ |
The correct answer is Option (1) → $2 x-5 y-16 z+13=0$ |
