CUET Preparation Today
If the points (2, 1), (-1, 4) and (a, 3) are collinear then the value/(s) of a is/(are): |
1, 2 3, 0 0 2, 1 |
0 |
The correct answer is Option (3) - 0 given points → collinear $Δ=\begin{vmatrix}2&1&1\\-1&4&1\\a&3&1\end{vmatrix}$ $⇒R_2→R_2-R_1,R_3→R_3-R_1$ $\begin{vmatrix}2&1&1\\-3&3&0\\a-2&2&0\end{vmatrix}=0$ $⇒-6-3a+6=0$ $⇒a=0$ |
