What is the value of last three digits of the product 2345×4567?

The correct answer is option (1) : 615

We will calculate $(2345×4567) mod\, 1000 $

$2345= 345 (mod\, 1000)$

$4567= 567(mod\, 1000)$

$2345×4567=345 ×567(mod \, 1000)$

$≡195615(mod\, 1000)$

$≡615(mod\, 100)$

Hence, the last 3 digits of the product $2345 ×4567$ are 615.