Two stations R and S are 400 km apart from each other. A train leaves from R to S and simultaneously another train leaves from S to R. Both trains meet after 10 hours. If the speed of the first train is 4 km/hr more than the second train, then what is the speed of the slower train?
Answer & explanation
Correct answer: option 1
Let speed of train 1 = x km/hr
Speed of train 2 = ( x+4) km/hr
According to question ,
Relative speed = \(\frac{400}{10}\) = 40 km/hr
Now ,
x + x + 4 = 40
2x = 36 km/hr
x = 18 km/hr
& x + 4 = 22 km/hr
So , Speed of slower train = 18 km/hr