Practicing Success
Practicing Success
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In the study of transistor as amplifier, if $α=\frac{I_C}{I_E}$ and $β=\frac{I_C}{I_B}$, where $I_C,I_B$ and $I_E$ are the collector, base and emitter currents, then |
$β=\frac{(1+α)}{α}$ $β=\frac{(1-α)}{α}$ $β=\frac{α}{(1-α)}$ $β=\frac{α}{(1+α)}$ |
$β=\frac{α}{(1-α)}$ |
As we know that $I_e = I_c + I_b$ Divide both side by $I_e$ $\frac{I_e}{I_c}=1+\frac{I_b}{I_c}⇒\frac{1}{α}=1+\frac{1}{β}$ $β=\frac{α}{1-α}$ |
