If secx = 7x and tanx =$\frac{7}{x}$

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If secx = 7x and tanx = $\frac{7}{x}$

find the value of 98(x²- $\frac{1}{x^2}$ )+2.

Options:

Correct Answer:

Explanation:

We know that sec²x - tan²x = 1

(7x)² - ( $\frac{7}{x}$ )²=1

49x² - $\frac{49}{x^2}$ = 1

49(x²- $\frac{1}{x^2}$ ) = 1

x²- $\frac{1}{x^2}$ = $\frac{1}{49}$ ⇒ Put in find

⇒ 98( $\frac{1}{49}$ )+2

= 4