What is the molality of solution when 39 g of benzene (C6H6) is dissolved in 100 g of water?
Answer & explanation
Correct answer: option 1
39 g benzene (0.5 mole), molecular mass of benzene=78 g
m=\(\frac{\text{no of moles}}{\text{mass of solvent (g)}}\)x1000
m=\(\frac{0.5}{100}\)x1000
m=5