Practicing Success
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What is the molality of solution when 39 g of benzene (C6H6) is dissolved in 100 g of water? |
5 4.5 4 50 |
5 |
39 g benzene (0.5 mole), molecular mass of benzene=78 g m=\(\frac{\text{no of moles}}{\text{mass of solvent (g)}}\)x1000 m=\(\frac{0.5}{100}\)x1000 m=5 |
