In an AC generator, a 100 turns coil of area $0.10\, m^2$ rotates at 50 Hz in a uniform magnetic field of 0.01 T. The maximum voltage generated in the coil is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 31.4 V
$E_{\max} = N B A \omega$
$\omega = 2\pi f = 2\pi \times 50 = 100\pi$
$E_{\max} = 100 \times 0.01 \times 0.10 \times 100\pi$
$E_{\max} = 10\pi$
$E_{\max} \approx 31.4 \ \text{V}$
The maximum voltage generated is $31.4 \ \text{V}$.