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What is the area of an equilateral triangle of side $4\sqrt{3}$ cm ? |
$15\sqrt{3}$ cm2 $16\sqrt{3}$ cm2 $20\sqrt{3}$ cm2 $12\sqrt{3}$ cm2 |
$12\sqrt{3}$ cm2 |
The side of a equilateral triangle = $4\sqrt{3}$ Then the area of a equilateral triangle = \(\frac{ \sqrt {3}}{4}\) (side)2 = \(\frac{ \sqrt {3}}{4}\) ($4\sqrt{3}$)2 = \(\frac{ \sqrt {3}}{4}\) (48) = $12\sqrt{3}$ cm2 |
