What is the area of an equilateral triangle of side $4\sqrt{3}$ cm ?
Answer & explanation
Correct answer: option 4
The side of a equilateral triangle = $4\sqrt{3}$
Then the area of a equilateral triangle = \(\frac{ \sqrt {3}}{4}\) (side)2
= \(\frac{ \sqrt {3}}{4}\) ($4\sqrt{3}$)2
= \(\frac{ \sqrt {3}}{4}\) (48)
= $12\sqrt{3}$ cm2