A and B together can complete a certain work in 20 days whereas B and C together can complete it in 24 days. If A is twice as good a work man as C, then in what time will B alone do 40% of the same work?
Answer & explanation
Correct answer: option 1
A + B = 20 days,
B + C = 24 days,
As Given,
A is twice efficient than C, therefore
⇒ A : C = 2 : 1 (Efficiency)
⇒ A + B = 6, B + C = 5,
Solving the efficiencies we get all the efficiencies, i.e;
A = 2, B = 4, C = 1,
⇒ Time taken by B to complete 40% of the total work is:
⇒ 40% of 120 = 48 units.
Hence, B will take = \(\frac{48}{4}\) = 12 days ..(\(\frac{Work}{Efficiency}\) = Time )