If the height and the radius of the base of a cone are both doubled, the volume of the cone becomes _______ of its previous volume.
Answer & explanation
Correct answer: option 2
Let the height and the radius of the cone = 1 and 1 respectively.
Then the volume of the cone = \(\frac{1}{3}\)πR2H = \(\frac{1}{3}\)π(1)2(1) = \(\frac{1}{3}\)π
If the height and the volume of the cone are doubled then the new volume = \(\frac{1}{3}\)π(2)2(2) = \(\frac{1}{3}\)π8
It will become 8 times to the previous volume.