Four alkali metals A, B, C and D are having respectively standard electrode potentials as –3.05, –1.66, –0.40, and 0.80 V. Which one will be most reducing?

A

To determine which alkali metal is the most reducing, we need to compare their standard electrode potentials. The more negative the standard electrode potential, the stronger the reducing agent.

Given the standard electrode potentials:
A: -3.05 V
B: -1.66 V
C: -0.40 V
D: 0.80 V

Among these, alkali metal A has the most negative standard electrode potential (-3.05 V). This indicates that alkali metal A is the strongest reducing agent among the given options.

Therefore, the correct answer is (1) A.