Solution of the differential equation
$x=1+x y \frac{d y}{d x}+\frac{(x y)^2}{2 !}\left(\frac{d y}{d x}\right)^2+\frac{(x y)^3}{3 !}\left(\frac{d y}{d x}\right)^3+...$ is
Answer & explanation
Correct answer: option 3
We have,
$x=e^{x y \frac{d y}{d x}}$
$\Rightarrow \log x=x y \frac{d y}{d x}$
$\Rightarrow y d y=\frac{\log x}{x} d x \Rightarrow y d y=\log x d(\log x)$
On integrating, we get
$\frac{y^2}{2} =\frac{(\log x)^2}{2}+C$
$\Rightarrow y^2 =\left(\log _e x\right)^2+2 C \Rightarrow y= \pm \sqrt{\left(\log _e x\right)^2+2 C}$