Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Waves

Question:

A plane electromagnetic wave of frequency 40 MHz travels in free space in the X-direction. At some point and at some instant, the electric field E has its maximum value of 750 N/C in Y-direction, the magnitude and direction of magnetic field will be:

Options:

2.5 µT in X-direction

2.5 µT in Y-direction

2.5 µT Z-direction

none of these

Correct Answer:

2.5 µT Z-direction

Explanation:

$B_m=\frac{E_m}{C} = \frac{750}{3 \times 10^8}$ = 2.5 µT Z-direction