Find $\int x e^x \, dx$
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $xe^x - e^x + C$
Take first function as $x$ and second function as $e^x$. The integral of the second function is $e^x$.
Therefore,
$\int x e^x \, dx = x e^x - \int 1 \cdot e^x \, dx = x e^x - e^x + C.$