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Find $\int x e^x \, dx$ |
$e^x(x + 1) + C$ $x e^x + e^x + C$ $xe^x - e^x + C$ $x^2 e^x - e^x + C$ |
$xe^x - e^x + C$ |
The correct answer is Option (3) → $xe^x - e^x + C$ Take first function as $x$ and second function as $e^x$. The integral of the second function is $e^x$. Therefore, $\int x e^x \, dx = x e^x - \int 1 \cdot e^x \, dx = x e^x - e^x + C.$ |
