When current changes from 14 A to 6 A in 0.5 sec through a coil, the emf induced is 4×10-4 . The coefficient of self induction is:
Answer & explanation
Correct answer: option 3
Self induce emf is given by e = -Ldi/dt
4x10-4 = -L [(6-14)/0.5]
= -L (-8/0.5)
L = (4x10-4x 0.5)/8
= 25x10-6H