If 4x4 - 37x2 + 9 = 0, x > $\sqrt{\frac{3}{2}}$, then what is the value of 8x3 - $\frac{27}{x^3}$ ?

35 215 -215 -35

215

4x4 - 37x2 + 9 = 0 Let us consider x2 = m = 4m2 – 37m + 9 = 0 = 4m2 – 36m - m + 9 = 0 = 4m(m - 9) - 1(m - 9) = 0 = (4m - 1)(m - 9) = 0 a = \(\frac{1}{4}\) or a = 9 a = x2 = 9 x = 3 8x3 - $\frac{27}{x^3}$ = 8 × 33 - $\frac{27}{3^3}$ = 216 - 1 = 215