The magnetic field strength in silicon is 1000 A/m. If its magnetic susceptibility is $-0.3 × 10^{-5}$, then the intensity of magnetization will be:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $-3 × 10^{-3} A/m$
Given:
Magnetic field strength, $H = 1000 \, A/m$
Magnetic susceptibility, $\chi = -0.3 \times 10^{-5}$
Formula:
$I = \chi H$
Substitute:
$I = (-0.3 \times 10^{-5}) \times 1000$
$I = -3 \times 10^{-3} \, A/m$
∴ The intensity of magnetization is $-3 \times 10^{-3} \, A/m$.