The magnetic field strength in silicon is 1000 A/m. If its magnetic susceptibility is $-0.3 × 10^{-5}$, then the intensity of magnetization will be:

$-3 × 10^{-3} A/m$

The correct answer is Option (2) → $-3 × 10^{-3} A/m$

Given:

Magnetic field strength, $H = 1000 \, A/m$

Magnetic susceptibility, $\chi = -0.3 \times 10^{-5}$

Formula:

$I = \chi H$

Substitute:

$I = (-0.3 \times 10^{-5}) \times 1000$

$I = -3 \times 10^{-3} \, A/m$

∴ The intensity of magnetization is $-3 \times 10^{-3} \, A/m$.