The magnetic field strength in silicon is 1000 A/m. If its magnetic susceptibility is \( -0.3 \times 10^{-5} \), then the intensity of magnetization will be:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \( -3 \times 10^{-3}\,\mathrm{A/m} \)
The magnetic susceptibility is the ratio of the intensity of magnetisation to the magnetic field strength.
\( \displaystyle \chi = \frac{M}{H} \;\Rightarrow\; M = \chi H \)
\( \displaystyle M = (-0.3\times10^{-5}) \times 1000\,\mathrm{A/m} = -3\times10^{-3}\,\mathrm{A/m} \)
The negative sign shows that silicon is diamagnetic: its magnetisation is opposite to the applied field.