Define a function $f:[-2,2] \rightarrow [-2,2]$ as $f(x)=[x]$, where $[x]$ denotes the greatest integer less or equal to x. Then $f$ is discontinuous at

every point between 1 & 2 Only at the point 2 -1,0,1,2 Only at -2

-1,0,1,2

$f(x)=\begin{cases}-2& \text{if}\hspace{.2cm} -2\leq x < -1\\ -1,& \text{if}\hspace{.2cm} -1\leq x< 0\\ 0,& \text{if}\hspace{.2cm} 0\leq x< 1\\ 1& \text{if}\hspace{.2cm} 1\leq x< 2\\ 2 & \text{if}\hspace{.2cm} x=2\\ \end{cases}$. \\Drawing the graph of $f$ and also by checking directly we can see $f$ is discontinuous at $-1,0,1,2$.