Practicing Success
If n is the number of sides, then the number of diagonals of a polygon is: |
\(\frac{n }{ 2}\) \(\frac{ n}{ 3}\) \(\frac{n(n-3) }{2 }\) \(\frac{ n(n-3)}{3 }\)
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\(\frac{n(n-3) }{2 }\) |
For a quadrilateral, n = 4 \(\frac{n(n-3) }{2 }\) \(\frac{4(4-3)) }{2 }\) = 2 Thus, a quadrilateral has two diagonals. |