If n is the number of sides, then the number of diagonals of a polygon is:
Answer & explanation
Correct answer: option 3
For a quadrilateral, n = 4
\(\frac{n(n-3) }{2 }\)
\(\frac{4(4-3)) }{2 }\) = 2
Thus, a quadrilateral has two diagonals.
If n is the number of sides, then the number of diagonals of a polygon is:
Correct answer: option 3
For a quadrilateral, n = 4
\(\frac{n(n-3) }{2 }\)
\(\frac{4(4-3)) }{2 }\) = 2
Thus, a quadrilateral has two diagonals.