Target Exam

CUET

Subject

Maths. Section B1

Chapter

Continuity and Differentiability

Question:

Differentiate the function $\log_7(\log x)$ with respect to $x$.

Options:

$\frac{1}{x \log x}$

$\frac{\ln 7}{x \log x}$

$\frac{1}{\log x \ln 7}$

$\frac{1}{x \log x \ln 7}$

Correct Answer:

$\frac{1}{x \log x \ln 7}$

Explanation:

The correct answer is Option (4) → $\frac{1}{x \log x \ln 7}$ ##

Let $y = \log_7(\log x) = \frac{\log(\log x)}{\log 7}$ (by change of base formula).

The function is defined for all real numbers $x > 1$. Therefore

$\frac{dy}{dx} = \frac{1}{\log 7} \frac{d}{dx}(\log(\log x))$

$= \frac{1}{\log 7} \frac{1}{\log x} \cdot \frac{d}{dx}(\log x)$

$= \frac{1}{x \log 7 \log x}$