Match List - I with List - II.
| List - I | List - II |
|---|---|
| (A) Plasmid of Salmonella | (I) Join foreign DNA to plasmid |
| (B) Restriction enzymes | (II) Insertional inactivation |
| (C) Ligases | (III) Construction of 1st recombinant DNA |
| (D) β-galactosidase | (IV) Molecular scissors |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
(A) Plasmid of Salmonella — this matches (III) Construction of 1st recombinant DNA. Cohen and Boyer joined an antibiotic resistance gene to a plasmid of Salmonella typhimurium in 1972.
(B) Restriction enzymes — this matches (IV) Molecular scissors. They cut DNA at specific sequences.
(C) Ligases — this matches (I) Join foreign DNA to plasmid. DNA ligase seals the cut ends together.
(D) β-galactosidase — this matches (II) Insertional inactivation. An insert inside its gene stops the enzyme, so recombinant colonies stay colourless.