Match List - I with List - II.
| List - I | List - II |
| (A) Initiation factor | (I) Tailing |
| (B) Introns | (II) Rho(p) |
| (C) Termination factor | (III) Sigma (o) |
| (D) Adenylate residue | (IV) Splicing |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) - (A) - (III), (B) - (IV), (C) - (II), (D) - (I)
| List - I | List - II |
| (A) Initiation factor | (III) Sigma (σ) |
| (B) Introns | (IV) Splicing |
| (C) Termination factor | (II) Rho(ρ) |
| (D) Adenylate residue | (I) Tailing |
In bacteria RNA polymerase is only capable of catalysing the process of elongation. It associates transiently with initiation-factor (σ) and termination-factor (ρ) to initiate and terminate the transcription, respectively. Association with these factors alter the specificity of the RNA polymerase to either initiate or terminate .
The second complexity is that the primary transcripts contain both the exons and the introns and are non-functional. Hence, it is subjected to a process called splicing where the introns are removed and exons are joined in a defined order. hnRNA undergoes additional processing called as capping and tailing.
In tailing, adenylate residues (200-300) are added at 3'-end in a template independent manner.