CUET Preparation Today
Match List - I with List - II.
Choose the correct answer from the options given below: |
(A) - (IV), (B) - (III), (C) - (II), (D) - (I) (A) - (III), (B) - (II), (C) - (IV), (D) - (I) (A) - (IV), (B) - (III), (C) - (I), (D) - (II) (A) - (III), (B) - (IV), (C) - (II), (D) - (I) |
(A) - (III), (B) - (IV), (C) - (II), (D) - (I) |
The correct answer is Option (4) - (A) - (III), (B) - (IV), (C) - (II), (D) - (I)
The RNA polymerase is only capable of catalysing the process of elongation. It associates transiently with initiation-factor (σ) and termination-factor (ρ) to initiate and terminate the transcription, respectively. Association with these factors alter the specificity of the RNA polymerase to either initiate or terminate . The second complexity is that the primary transcripts contain both the exons and the introns and are non-functional. Hence, it is subjected to a process called splicing where the introns are removed and exons are joined in a defined order. hnRNA undergoes additional processing called as capping and tailing. In tailing, adenylate residues (200-300) are added at 3'-end in a template independent manner. |
