Which of the following is the true statement about [PtCl2(NH3)2] (Electronic configuration of Pt: [Xe]5d86s2) ?

A tetrahedral geometry and is paramagnetic in behaviour A tetrahedral geometry and is diamagnetic in behaviour A square planar geometry and is paramagnetic in behaviour A square planar geometry and is diamagnetic in behaviour

A square planar geometry and is diamagnetic in behaviour

The correct answer is option 4. A square planar geometry and is diamagnetic in behaviour. Oxidation state of NH3​ in the given compound $=0$ Oxidation state of $Cl$ in the given compound $=-1$ Let $x$ be the oxidation state of $Pt$ in the given compound. Therefore, $x+2\left(-1\right)+2\left(0\right)=0$ $\Rightarrow x=+2$ O.S. of Pt (Z = 78) in the complex is +2 (Pt2+) Pt2+:[Xe]4f145d8 The eight electrons in $5d$-subshell pair up in four $d$-orbitals followed by dsp2-hybridisation, The shape of the complex is square planar.