CUET Preparation Today
The equation of plane which cuts equal intercepts of unit length on the coordinate axes is: |
$x+y+z=3$ $x+y-z=1$ $x+y+z=1$ $x+y+z=0$ |
$x+y+z=1$ |
The correct answer is Option (3) - $x+y+z=1$ Let intercepts be a, b, c (on x, y, z axis respectively) $a= b= c=1$ so equation → $\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1$ so $x+y+z=1$ |
