CUET Preparation Today
Calculate the magnetic moment of [Fe(CN)6]4-. |
\(\sqrt{24}\) B.M. \(\sqrt{15}\) B.M. \(\sqrt{35}\) B.M. Zero |
Zero |
In [Fe(CN)6]4- ion x + 6(-1) = -4 x - 6 = -4 x = -4 + 6 = 2 Fe2+: [Ar]3d6 But CN- is a strong field ligand and it will pair up all the electrons. Hence, Magnetic moment is zero. |
