The self inductance of a coil is 200 μH, current changes by 1 A in 0.05 sec. What is the emf produced?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 4 mV
The emf produced (ε) in a coil -
$ε=-L\frac{ΔI}{Δt}$
where,
$L=200μH=200×10^{-6}H$
$ΔI=1A$
$Δt=0.05$
$ε=-(200×10^{-6})×\frac{1}{0.05}=4 mV$