Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Induction

Question:

The self inductance of a coil is 200 μH, current changes by 1 A in 0.05 sec. What is the emf produced?

Options:

5 mV

2 mV

1 mV

4 mV

Correct Answer:

4 mV

Explanation:

The correct answer is Option (4) → 4 mV

The emf produced (ε) in a coil -

$ε=-L\frac{ΔI}{Δt}$

where,

$L=200μH=200×10^{-6}H$

$ΔI=1A$

$Δt=0.05$

$ε=-(200×10^{-6})×\frac{1}{0.05}=4 mV$