The self inductance of a coil is 200 μH, current changes by 1 A in 0.05 sec. What is the emf produced? |
5 mV 2 mV 1 mV 4 mV |
4 mV |
The correct answer is Option (4) → 4 mV The emf produced (ε) in a coil - $ε=-L\frac{ΔI}{Δt}$ where, $L=200μH=200×10^{-6}H$ $ΔI=1A$ $Δt=0.05$ $ε=-(200×10^{-6})×\frac{1}{0.05}=4 mV$ |