Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Organic: Biomolecules

Question:

Consider the following statements:

A. Monosaccharides are optically active polyhydroxy carbonyl compounds

B. Fructose does not reduce Fehling’s solution because it is a ketose

C. α-D(+)-glucose and β-D(+)-glucose are anomers

D. D-glucose and D-mannose are C-2 epimers

Which of the following statements are correct?

Options:

A, B and C

A, C and D

A, B and D

B, C and D

Correct Answer:

A, C and D

Explanation:

The correct answer is (2) A, C and D.

Statement A: Monosaccharides are optically active polyhydroxy carbonyl compounds.

This statement is correct. Monosaccharides are carbohydrates that contain one carbonyl group (a ketone or an aldehyde) and several hydroxyl groups. They are optically active, which means that they rotate the plane of polarized light.

Statement B: Fructose does not reduce Fehling’s solution because it is a ketose.

This statement is correct. Fructose is a ketose, which means that it has a carbonyl group at the end of the molecule. Ketoses do not reduce Fehling's solution, while aldoses do.

Statement C: α-D(+)-glucose and β-D(+)-glucose are anomers.

This statement is correct. Anomers are stereoisomers of monosaccharides that differ in the configuration of the hydroxyl group at the anomeric carbon (the carbon atom next to the carbonyl group). α-D(+)-glucose and β-D(+)-glucose are anomers of glucose.

Statement D: D-glucose and D-mannose are C-2 epimers.

This statement is correct. Epimers are stereoisomers of monosaccharides that differ in the configuration of only one of the hydroxyl groups. D-glucose and D-mannose differ in the configuration of the hydroxyl group at the C-2 atom.

Therefore, Statements A, C, and D are all correct.