What is the radius of gyration of a uniform rod whose length is L and passes through the centre of mass ?
Answer & explanation
Correct answer: option 2
Radius of gyration : k
\(I = \frac{1}{12} mL^2\)
Now, as mk2 = I
\(\Rightarrow mk^2 = \frac{1}{12} mL^2\)
\(\Rightarrow k = \frac{1}{\sqrt{12}}\)
and \(\Rightarrow k = \frac{1}{2\sqrt{3}}\)