Practicing Success
What is the radius of gyration of a uniform rod whose length is L and passes through the centre of mass ? |
\(\frac{L}{\sqrt{3}}\) \(\frac{L}{2\sqrt{3}}\) \(\frac{L}{\sqrt{2}}\) \(\frac{L^2}{12}\) |
\(\frac{L}{2\sqrt{3}}\) |
Radius of gyration : k \(I = \frac{1}{12} mL^2\) Now, as mk2 = I \(\Rightarrow mk^2 = \frac{1}{12} mL^2\) \(\Rightarrow k = \frac{1}{\sqrt{12}}\) and \(\Rightarrow k = \frac{1}{2\sqrt{3}}\) |