The magnetic moment of a transition metal of 3d series is \(\sqrt {35}\) B.M. What will be its electronic configuration?
Answer & explanation
Correct answer: option 2
25Mn : [Ar]4s23d5
Magnetic moment, u = \(\sqrt {n(n+2)}\)
no of unpaired electrons = 5
u = \(\sqrt {5(5+2)}\) = \(\sqrt {35}\)B.M.