CUET Preparation Today
In the given figure if points B and D are at same potential then the value of x is:
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$2 \Omega$ $3 \Omega$ $4 \Omega$ $6 \Omega$ |
$3 \Omega$ |
The correct answer is Option (2) → $3 \Omega$ Using wheatstone bridge, $\frac{R_1}{R_2}=\frac{R_1'}{R_2'}$ $∴\frac{\frac{6x}{x+6}}{5}=\frac{6}{15}$ $\frac{6x}{x+6}=2$ $⇒6x=2x+12$ $⇒x=3Ω$ |
