In the given figure if points B and D are at same potential then the value of x is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $3 \Omega$
Using wheatstone bridge,
$\frac{R_1}{R_2}=\frac{R_1'}{R_2'}$
$∴\frac{\frac{6x}{x+6}}{5}=\frac{6}{15}$
$\frac{6x}{x+6}=2$
$⇒6x=2x+12$
$⇒x=3Ω$