In the figure given below, three capacitors of capacitance C1 = 20 μF, C2 = 30 μF, and C3 = 50 μF are connected. The equivalent capacitance of the combination between the points A and B will be:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 25 μF
From the figure, C1 and C2 are connected between the same two wires, so they are in parallel. This pair is then joined to B through C3, so it is in series with C3.
\( C_{12} = C_1 + C_2 = 20 + 30 = 50\,\mu\mathrm{F} \)
\( \displaystyle \frac{1}{C_{\mathrm{eq}}} = \frac{1}{C_{12}} + \frac{1}{C_3} = \frac{1}{50} + \frac{1}{50} \)
\( C_{\mathrm{eq}} = 25\,\mu\mathrm{F} \)