CUET Preparation Today
$\int a^{a^{a^x}} . a^{a^{a^x}} . a^x dx$ is equal to |
$\frac{a^{a^x}}{(\log a)^3}+c$ $a^{a^{a^x}}(\log a)^3+c$ $\frac{a^{a^{a^x}}}{(\log a)^3}+c$ none of these |
$\frac{a^{a^{a^x}}}{(\log a)^3}+c$ |
Put ax = t ∴ I = $\int \frac{a^{a^t} . a^t d t}{\log a}$ again put at = z ∴ I = $\int \frac{a^z d z}{\log a}=\frac{a^z}{(\log a)^3}+c=\frac{a^{a^{a^x}}}{(\log a)^3}+c$ Hence (3) is the correct answer. |
