The value of $\lambda$ and $\mu$ if $(2 \hat{i}+6 \hat{j}+27 \hat{k}) \times(\hat{i}+\lambda \hat{j}+\mu \hat{k})=\vec{0}$ are respectively:

$3, \frac{27}{2}$ $-\frac{27}{2}, 3$ $-1, \frac{11}{3}$ $-\frac{5}{3}, \frac{7}{3}$

$3, \frac{27}{2}$

The correct answer is Option (1) - $3, \frac{27}{2}$