Practicing Success
The differential equation whose solution is $A x^2+B y^2=1$ where A and B are arbitrary constant is of: (A) first order and first degree Choose the correct answer from the options given below: |
(D) Only (C) and (D) Only (B) and (D) Only (A) Only |
(B) and (D) Only |
The correct answer is Option (3) - (B) and (D) Only |