The value of $\frac{2 cos^3 θ−cos θ}{sin θ−2 sin^3 θ}$ is:
Answer & explanation
Correct answer: option 3
\(\frac{2 cos³θ - cosθ}{sinθ - 2sin³θ }\)
= \(\frac{cosθ(2 cos²θ - 1)}{sinθ( 1 - 2sin²θ) }\)
{ using , 2 cos²θ - 1 = cos 2θ = 1 - 2sin²θ }
= \(\frac{cosθ}{sinθ }\)
= cotθ