Circumference of a circle is 58π cm. There is a chord XY of length 42 cm in this circle. What is the distance of this chord XY from the centre?
Answer & explanation
Correct answer: option 2
In triangle XOP
XP = 21 cm
OX = 29 cm
Apply Pythagoras theorem
\( {OX }^{2 } \) = \( {OP }^{2 } \) + \( {XP }^{ 2} \)
\( {29}^{2 } \) = \( {OP }^{2 } \) + \( {21 }^{ 2} \)
\( {OP }^{2 } \) = 841 - 441
( {OP }^{2 } \) = 40
OP = 20
Therefore, Distance of this chord XY from the center is 20 cm.