Circumference of a circle is 58π cm. There is a chord XY of length 42 cm in this circle. What is the distance of this chord XY from the centre?

20 cm

In triangle XOP

XP = 21 cm

OX = 29 cm

Apply Pythagoras theorem

\( {OX }^{2 } \) = \( {OP }^{2 } \) + \( {XP }^{ 2} \)

\( {29}^{2 } \) = \( {OP }^{2 } \) + \( {21 }^{ 2} \)

\( {OP }^{2 } \) = 841 - 441

( {OP }^{2 } \) = 40

OP = 20

Therefore, Distance of this chord XY from the center is 20 cm.