In a ΔABC right angled at B if AB=4 cm and ∠C=60°, then length of AC…

If we consider the common term = 1 and if the angle of this triangle is = 60^o

Then, BC = 1

AB = \(\sqrt {3}\)

and AC = 2

 

AB = 4

 \(\sqrt {3}\)  =  4

1= \(\frac{4}{\sqrt {3}}\)

then the value of AC = 2 = \(\frac{4}{\sqrt {3}}\) × 2 = \(\frac{8}{\sqrt {3}}\) 

Divide and multiply by \(\sqrt {3}\) on both numerator and denominator

= \(\frac{8}{\sqrt {3}}\) × \(\frac{\sqrt {3}}{\sqrt {3}}\) = $\frac{8\sqrt{3}}{3}$ cm