Practicing Success
In a ΔABC right angled at B if AB=4 cm and ∠C=60°, then length of AC is : |
$\frac{8\sqrt{3}}{3}$ cm $\frac{2}{\sqrt{3}}$ cm $\sqrt{3}$ cm $\frac{1}{\sqrt{3}}$ cm |
$\frac{8\sqrt{3}}{3}$ cm |
If we consider the common term = 1 and if the angle of this triangle is = 60o Then, BC = 1 AB = \(\sqrt {3}\) and AC = 2
AB = 4 \(\sqrt {3}\) = 4 1= \(\frac{4}{\sqrt {3}}\) then the value of AC = 2 = \(\frac{4}{\sqrt {3}}\) × 2 = \(\frac{8}{\sqrt {3}}\) Divide and multiply by \(\sqrt {3}\) on both numerator and denominator = \(\frac{8}{\sqrt {3}}\) × \(\frac{\sqrt {3}}{\sqrt {3}}\) = $\frac{8\sqrt{3}}{3}$ cm |