The IUPAC name of the following compound is

The correct answer is Option (1) → 3-Bromocyclohexanol

In a substituted cycloalkanol, the –OH group is the principal group and is named by the suffix -ol; the ring carbon carrying it is C1. The ring is then numbered in the direction that gives the substituents the lowest locants, and the halogen is written as a prefix.

The given compound is a six-membered ring (cyclohexane) with –OH on one carbon and Br on a carbon separated from it by one ring carbon. Starting at the C–OH carbon and going the short way round, Br is on C3 (going the other way it would be C5). The name is 3-bromocyclohexanol (3-bromocyclohexan-1-ol).