The equation of a plane passing through the points (1, 2, 3), (4, 2, 3) and (-1, 0, 6) is given by:

$3 y-2 z+12=0$ $9 y+18-6 z=0$ $3 y+2 z+12=0$ $-3 y-2 z+12=0$

$-3 y-2 z+12=0$

The correct answer is Option (4) - $-3 y-2 z+12=0$