Practicing Success
A beaker is filled with a liquid, 3 parts of which are water and 7 parts some medicine. What part of the mixture should be replaced with water so that that the resultant mixture has water and medicine in a ratio 1:1? |
$\frac{2}{7}$ $\frac{1}{7}$ $\frac{2}{5}$ $\frac{1}{5}$ |
$\frac{2}{7}$ |
Let the beaker contains 10 litres of liquid. ⇒ Amount of water = 3 L, Amount of Medicine = 7 L, ⇒ Let x litres of this liquid be replace with water. ⇒ Now, Water = $\frac{3x}{10}$ and Medicine = $\frac{7x}{10}$ ⇒ Water before replacement + $\frac{7x}{10}$ = Medicine before replacement = $\frac{7x}{10}$ + $\frac{7x}{10}$ = $\frac{7x}{5}$ ⇒ $\frac{7}{10}$ part - $\frac{3}{10}$ part = $\frac{7x}{5}$ ⇒ $\frac{2}{5}$ part = $\frac{7x}{5}$ ⇒ x = $\frac{2}{7}$ Hence, the part of mixture which should be replaced with water is $\frac{2}{7}$. |