Match List I with List II
| List I | List II |
| A. Reimer-Tiemann reaction | I. Benzene |
| B. Kolbe's reaction | II. Picric acid |
| C. Nitration of phenol with conc. \(HNO_3\) | III. Salicylic acid |
| D. Reaction of phenol with Zn dust | IV. Salicylaldehyde |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is option 2. A-IV, B-III, C-II, D-I.
| List I | List II |
| A. Reimer-Tiemann reaction | IV. Salicylaldehyde |
| B. Kolbe's reaction | III. Salicylic acid |
| C. Nitration of phenol with conc. \(HNO_3\) | II. Picric acid |
| D. Reaction of phenol with Zn dust | I. Benzene |
Let us match the reactions in List I with their corresponding products or key reactants in List II.
A. Reimer-Tiemann reaction: IV. Salicylaldehyde
The Reimer-Tiemann reaction involves the conversion of phenol to salicylaldehyde by reacting phenol with chloroform (\(CHCl_3\)) in the presence of a strong base like sodium hydroxide (\(NaOH\)).
B. Kolbe's reaction: III. Salicylic acid
The Kolbe's reaction involves the carboxylation of phenol (through its sodium salt) to produce salicylic acid when treated with carbon dioxide (\(CO_2\)) under high pressure.
C. Nitration of phenol with concentrated \(HNO_3\): II. Picric acid
When phenol is treated with concentrated nitric acid, it undergoes nitration to produce picric acid (2,4,6-trinitrophenol).
D. Reaction of phenol with Zn dust :I. Benzene
When phenol is heated with zinc dust, it reduces to benzene.
