CUET Preparation Today
Match List I with List II
Choose the correct answer from the options given below: |
A-I, B-II, C-III, D-IV A-IV, B-III, C-II, D-I A-II, B-III, C-IV, D-I A-III, B-II, C-I, D-IV |
A-IV, B-III, C-II, D-I |
The correct answer is option 2. A-IV, B-III, C-II, D-I.
Let us match the reactions in List I with their corresponding products or key reactants in List II. A. Reimer-Tiemann reaction: IV. Salicylaldehyde The Reimer-Tiemann reaction involves the conversion of phenol to salicylaldehyde by reacting phenol with chloroform (\(CHCl_3\)) in the presence of a strong base like sodium hydroxide (\(NaOH\)).
The Kolbe's reaction involves the carboxylation of phenol (through its sodium salt) to produce salicylic acid when treated with carbon dioxide (\(CO_2\)) under high pressure.
C. Nitration of phenol with concentrated \(HNO_3\): II. Picric acid When phenol is treated with concentrated nitric acid, it undergoes nitration to produce picric acid (2,4,6-trinitrophenol).
D. Reaction of phenol with Zn dust :I. Benzene When phenol is heated with zinc dust, it reduces to benzene.
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